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41). Fredrick after spending 20% of his monthly salary in buying electronic goods and 10% of the monthly salary in repair work of furniture, invested 30% of the remaining amount in fixed deposits. If he was left with Rs 18,963/-, how much is his monthly salary ?
Let the monthly salary be x According to question, = \( x \times \frac{70}{100} \times \frac{70}{100} = 18963 \) x = Rs.38,700/- | ||||||

42). The total price of 6 trousers and 5 shirts is Rs 2,340/-. The total price of 7 shirts is Rs 540 more than the total price of 3 trousers.What is the total price of 4 shirts ?
Let the price of one trouserrs be Rs.x and the price of one shirt be Rs.y According to question, 5y + 6x = 2340 ---- (i) 7y - 3x = 540 --- (ii) On multiplying equation (ii) by 2 and adding in eqution (i), we get 19y = 3420 y = 180 | ||||||

43). In a village, 30% of the villagers belong to upper economic class. The number of Villagers who belong to middle economic class are 3/2 of the number of villagers who belong to lower economic class. If 6860 villagers belong to lower economic class, what is the population of the village ?
Villagers belong to lower eonomic class = 6860 Villageers belong to middle eonomic class = \( \frac{30}{100}x+10290+6860=x \) 17150 = \( x - \frac{3}{10}x \) \( \frac{17150 \times 10}{7} = x \) x = 24500 | ||||||

44). A water tank has one inlet, A and one outlet, B'. A takes 5 hours to fill the empty tank, when B is not open and B takes 8 hours to empty the full tank, if the tank is three fifth full, how much time will it take to fill the tank completely when both A and B are opened simultaneously ? (in hours)
If the tank is \( \frac{3}{5} \)th full, then remaining empty tank will be = \( 1 - \frac{3}{5} = \frac{2}{5} \)th And B can fill the empty tank in = \( \frac{5 \times 8}{8}- 5\) = \( \frac{40}{3} \) hour Then \( \frac{2}{5} \)th tank fill in = \( \frac{40}{3} \times \frac{2}{5}= 5\frac{1}{3} \)hoour | ||||||

45). The height and base of a triangle are equal to the length and breadth of a rectangle respectively. If the perimeter of the rectangle is 86m and the difference between its length and breadth is 5m, what is the area of' the triangle ? (in m2)
Let the length of rectangle be l m and breadth be b m According to question, l - b = 5 --- (i) Perimeter of rectangle = \( 2 \left(l+b\right)=86 \) l + b = 43 --- (ii) On soling equations (i) and (ii) we get, l = 24 m b = 19 m Height of triangle = Length of rectancle = 24 m and base of triangle = Breadth of reftangle = 19m Area of triangle= \( \frac{1}{2} \times 19 \times 24 = 228 m^{2} \) | ||||||

\( 7^{2} \times 3^{2} = ?^{2} - 135 \) \( 49 \times 9 = ?^{2} - 135 \) 441 + 135 = \( ?^{2} \) 576 = \( ?^{2} \) ? = \( \sqrt{576} = 24 \) | ||||||

47). \( \frac{1}{13} \times \sqrt{(2704)} = 84 - ? \)
\( \frac{1}{13} \times \sqrt{2704} = 84 - ? \) = \( \frac{1}{13} \times 52 = 84 - ? \) ? = 84 - 4 ? = 80 | ||||||

48). 912.0076 + 878.42 - 1671.35 = 368 - ?
912.0076+878.42-1671.35 = 368 - ? ? = 368-912.0076-878.42+1671.35 ? = 248.9224 | ||||||

49). \( 16\frac{2}{7} + 15\frac{1}{4} + 18\frac{1}{2} = ? \)
\( 16\frac{2}{7} + 15\frac{1}{4} + 18\frac{1}{2}=? \) \( 16+15+18 \left(\frac{2}{7}+\frac{1}{4}+\frac{1}{2} \right) \) = ? \( 49 \left(\frac{8+7+14}{28}\right) \) = ? \( 49 \frac{29}{28} \) = ? \( 50 \frac{1}{28} \) = ? | ||||||

50). \( (25)^{3} \times (4)^{3} - 800^{2} = (?)^{2} \)
\( \left(25\right)^{3} \times \left(4\right)^{3} - 800^{2} = \left(?\right)^{2} \) \( 15625 \times 64 - 640000 = \left(?\right)^{2} \) \( 1000000 - 640000 = \left(?\right)^{2} \) \( 360000 = \left(?\right)^{2} \) ? = 600 |